Time & Work NMAT 2023
| Q 1. Reema can complete a piece of work in 12 days while Seema can the same work in 18 days. If they both work together, then how many days will be required to finish the work?a. 6 days b. 7.2 days c. 9.5 days d. 12 days Q 2. If 'A' completes a piece of work in 3 days, which 'B' completes it in 5 days and 'C' takes 10 days to complete the same work. How long will they take to complete the work , if they work together? a. 1.5 days b. 4.5 days c. 7 days d. 9.8 days |
| Q 3. Two painters 'P1' & 'P2' paint the bungalow in 3 days. If P1 alone can paint the bungalow in 12 days, in how many days can 'P2'' alone complete the same paint work? a. 4 days b. 6 days c. 9 days d. 12 days Q 4. A & B can make paintings in 6 days, B & C can can make those paintings in 10 days. If A, B & C together can finish the work in 4 days, then A & C together will do it in ________ days.a. 4 (2/7) days b. 1/ 8 days c. 2 (2/5) days d. 6 (3/ 8) days |
| Q 5. Pooja is twice as efficient as Aarti and takes 90 days less than Aarti to complete the job. Find the time in which they can finish the job together. a. 30 days b. 45 days c. 60 days d. 90 days Q 6. Monika is twice as good as Sonika and together they complete a piece of work in 20 days. In how many days will Monika alone will finish the work?a. 22 days b. 30 days c. 37 days d. 52 days |
| Q 7. 6 men can pack 12 boxes in 7 days by working for 7 hours a day. In how many days can 14 men pack 18 boxes if they work for 9 hours a day? a. 3.5 days b. 5 days c. 7.5 days d. 12 days Q 8. 4 men and 5 boys can do a piece of work in 20 days while 5 men and 4 boys can do the same work in 16 days. In how many days can 4 men and 3 boys do the same work?a. 10 days b. 15 days c. 20 days d. 25 days |
Answer 1
Answer 2
Answer 3
Answer 4
Answer 5
Assume that Pooja completes the job in 'x' days.
So, Aarti will take '2x' days to complete the same job.
As Pooja takes 90 days less than Aarti, we get
x = 2x – 90
By solving this equation, we get x = 90 .
Thus, 2x = 2 x 90 = 180
Part of job done by Pooja in 1 day = 1/ 90
Part of job done by Aarti in 1 day = 1/180
(Part of job done together in 1 day) = (Part of job done by Pooja in 1 day) + (Part of job done by Aarti in 1 day)
= (1/90) + (1/180)
= 3/180
=1/60
(1/60)th part of whole job will be completed by Pooja and Aarti together in one day.
Therefore, the whole job will be completed in 60 days together.
Answer 6:
Correct answer : (b)
Hint: If 'A' is 'x' times as good a workman as 'B', then ratio of work done by A & B = x: 1
Monika's 1 day work : Sonika's 1 day work = 2:1
(Monika's + Sonika's ) 1 day work = 1 /20
Divide 1/20 in the ratio 2:1 ---------( To divide the number 'a' into ratio x & y , we have first part = ax / x + y )
| Therefore, Monika's 1 day work = 1/20 x (2/2+1) = 1/30. Hence, Monika will alone finish the work in 30 days. |
Answer 7:
Answer 8
Assume 1 man's 1 day work = x & 1 boy's 1 day work = y
From the given data, we can generate the equations as : 4x + 5y = 1/20 ---(1) & 5x + 4y = 1/16 ---(2)
By solving the simultaneous equations (1) & (2),
x = 1/ 80 & y = 0
| Therefore, (4 men + 3 boys ) 1 day work = 4 x 1/80 + 3 x 0 = 1/20 |
Frequently asked questions
What type of Time and Work questions does NMAT ask?
This set covers two/three people working together, painters/workers with different efficiencies, and comparative-efficiency problems (e.g. 'Pooja is twice as efficient as Aarti').
What's the core formula used across these questions?
Work done per day = 1/(days to finish alone); adding individual one-day work rates gives the combined one-day rate, whose reciprocal is the number of days together — this is used in every worked solution on the page.
Is there a worked example for 'efficiency' type questions?
Yes — Q5 (Pooja twice as efficient as Aarti, finishing 90 days sooner) is fully solved on the page: setting up x = 2x - 90 gives x = 90, and the combined time works out to 60 days.
How many questions are in this practice set?
Eight Time and Work questions are given with four options each, and worked solutions are shown for several of them.